Paper II Mathematics
- If A is a non-singular matrix of order 3, then adj (adjA) is equal t0
(A)
(B)
(C)
(D)
(E)
- If
, then the values of x, y and z are respectively
(A) 5, 2, 2
(B) 1, –2, 3
(C) 0, –3, 3
(D) 11, 8, 3
(E) 4, 1, 3 - Which one of the following is true always for any two non-singular matrices A and B of same order?
(A) AB = BA
(B) (AB)t = AtBt
(C) (A + B) (A – B) = A2 – B2
(D) (AB)-1 = B-1A-1
(E) AB = –BA - The solution set of the inequation
is
(A) (–∞, –11) ∪ (3, ∞)
(B) (–∞, –10) ∪ (2, ∞)
(C) (–100, –11) ∪ (1, ∞)
(D) (0, 5) ∪ (–1, 0)
(E) (–5, 0) ∪ (3, 7) - If 3 ≤ 3t – 18 ≤ 18, then which one of the following is true?
(A) 15 ≤ 2t + 1 ≤ 20
(B) 8 ≤ t < 12
(C) 8 ≤ t + 1 ≤ 13
(D) 21 ≤ 3t ≤ 24
(E) t ≤ 7 or t ≥ 12 - Let p : 7 is not greater than 4 and
q : Paris is in France
be two statements.
Then ∼(p ∨ q) is the statement
(A) 7 is greater than 4 or Paris is not in France
(B) 7 is not greater than 4 and Paris is not in France
(C) 7 is greater than 4 or Paris is in France
(D) 7 is not greater than 4 or Paris is not in France
(E) 7 is greater than 4 and Paris is not in France - If S(p, q, r) = (∼p) ∨ [∼(q ∨r)] is a compound statement, then S(∼p, ∼q, ∼r) is
(A) ∼S(p, q, r)
(B) S(p, q, r)
(C) p∨(q ∧ r)
(D) p ∨ (q ∨ r)
(E) S(p, q, ∼r) - For any two statements p and q, ∼ (p ∨ q) ∨ (∼p ∧ q) is logically equivalent to
(A) p
(B) ∼p
(C) q
(D) ∼q
(E) p ∨ q - If tan
, a > b > 0 and if
, then
is equal to
(A)
(B)
(C)
(D)
(E)
- If tan-1 (x + 2) + tan-1 (x – 2) – tan_1
= 0, then one of the values of x is equal to
(A) –1
(B) 5
(C)
(D) 1
(E)
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